[9996]

Here is a picture of our new 8010 coming off the line right before it gets it's casings.

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Here we are driving it out the door onto the lot

How much volume per hour in 80 bushel wheat with a 36' Macdon flex?

 

[combiness]

Give me your est ground speed and I can calculate that for you.

 

[larry]

The "general formula of thumb" used by the ag machinery industry to estimate rates of productivity at 82.5% efficiency, which is the generally accepted standard rate of agricultural machinery operations, including combines, is:


Ground speed x Width / 10 =


Ex. 1: 3.5 mph x 36 ft / 10 = 12.6 ac/hr

80 bu x 12.6 ac/hr = 1008 bph

Ex. 2: 4.0 mph x 36 ft / 10 = 14.4 ac/hr

80 bu x 14.4 ac/hr = 1152 bph

1008 - 1152 bushels per hour is a safe estimate of what you'll likely be able to cover with your new 8010 and 36 foot draper.



The "long" version of the above formula is:


Ground speed X feet x .825 / 8.25 =


Ex. 3.5 x 36 x .825 = 12.6 ac./hr.

Ex. 4 x 36 x .825 / 8.25 = 14.4 ac./hr.

 

[combiness]

I use that "long" version as a formula.

 

[rubberduck]

i reckon that formula never works in the real world though!

 

[larry]

I don't know what else could be used, there isn't really another formula that's going to give you any better or any significant different (advantageous) out come. You can adjust the efficiency rate in the long version to adjust to different applications and conditions. Combine efficiency rates take into account any down or idle time, opening a field, turning on the headlands, unloading, stopping to pick up the land lord, neighbor or kids to ride around, when Nature calls, the auger cart is full and all trucks are gone, etc. That's why I think 75% is more realistic rate of measure for harvesting. 82-85% is fine for tillage, etc. because you aren't relying on the support crew like harvesting. In harvesting, everyone has to run at 82.5%, not just the combine. Might take some of the fun out of it if so.

 

[rubberduck]

thats what i meant!

There is a good way of figurering your efficiancy rate out. Just look at your engine hours and seperator hours. Log them as you start on a new field and log them when you finish a field.

That will give you a pretty accurate idea. And honestly i think 75% as an average on the whole season is way too high. but i dont know to tell you the truth. Just like you pointed out Muddy, the combine itself is just a very little brick in the puzzle

 

[larry]

I'd say the avg. separator hours to engine hours on most farmer owned combines is going be in the 1/3 : 2/3 range (65-70% efficient).

 

[Don Boles]

Muddy your going to give up 21% productivity?
5280 X 3.5 X 36 / 43560 (sq ft / ac) = 15.2 not 12.6
By the way your simplified area calculation actually works metrically.
5.6 km X 11m = 61.6 / 10 = 6.16 ha
I'm sure I'll have all North American farmers converted to metric by sunset.
Or maybe when heck freezes over.
1 of the 2.

Don

 

[combiness]

Muddy, I really agree wth you, given the overal variabes. After all, this was more about overall efficiency, rather than a test of just acres/bu per hour, etc.

Yes, I use that formula to calculate just the above, but it won't tell me or anyone here, exactly what's done over a 10-16 hour day.

Simpler calculation is just header width x ground speed >acre for approx acres/hour. However, even that's not exact, counting for overlap, speed variances and so on.

Now you just gotta love acre counters, yield monitors and GPS!

 

[larry]

Muddy your going to give up 21% productivity?
5280 X 3.5 X 36 / 43560 (sq ft / ac) = 15.2 not 12.6
By the way your simplified area calculation actually works metrically.
5.6 km X 11m = 61.6 / 10 = 6.16 ha
I'm sure I'll have all North American farmers converted to metric by sunset.
Or maybe when heck freezes over.
1 of the 2.

Don

Don, your equation is correct, if you are not accounting for efficiency. Ground speed x Working Width / 10 is the productivity formula at 82.5% efficiency. I probably do give up 15-20% efficiency, just like you and everyone else does. Hence, the reason why 82.5% has been settled on by every mfg as the published / quoted generally accepted rate of efficiency.

 

[Don Boles]

I understand, interesting that an efficiency rating just happens to fit a simplified formula.
I'm impressed you think I'm 80% efficient.
You haven't seen our haywire harvest crew have you?

Don

 

[9996]

This machine is going to Alabama we no-till all of our grain crops, so we didn't need the mud hog. Other than that it has everything else. We also got the small tube rotor. No corn. Just soybeans and wheat.

 

[HighDesert]

9996, any chance you could take a picture or two of that small tube rotor so we can see what it looks like? Hope the machine works well for you!

 

[9996]

It is supposed to be in this coming week. I'll try to get some pics of the rotor and post them. We should be in wheat about the 10th of June.